The risk of breast cancer is strongly influenced by hormonal and reproductive factors, specifically those related to estrogen exposure.
One of the key protective factors against breast cancer is full-term pregnancy at an early age and having multiple pregnancies. This is because pregnancy leads to the differentiation of breast tissue, reducing the number of immature cells that are more vulnerable to malignant transformation. Additionally, during pregnancy and breastfeeding, the overall number of menstrual cycles is reduced, lowering cumulative lifetime estrogen exposure.
In contrast, nulliparous women, meaning women who have never given birth, have a higher lifetime exposure to estrogen and progesterone because they experience more menstrual cycles uninterrupted by pregnancy or breastfeeding. This prolonged hormonal exposure increases the risk of estrogen-receptor-positive breast cancers, which are the most common type.
Thus, the correct answer is nulliparous women, who have a significantly higher risk of developing breast cancer compared to women who have had multiple pregnancies.
🔍 Why the Other Options Are Incorrect
Multiparous women (those who have had multiple pregnancies) generally have a reduced risk of breast cancer because repeated pregnancies decrease lifetime estrogen exposure.
Primiparity refers to being pregnant for the first time. While late primiparity (first childbirth after age 30) is a risk factor, simply having a first pregnancy at an average age is not as high a risk as being nulliparous.
Diabetics have an increased risk of some cancers (like pancreatic, endometrial, and liver cancer), but diabetes is not a primary risk factor for breast cancer. Some studies suggest a mild association, but it is not as significant as reproductive factors.
Grand-multiparous women (those who have had five or more births) actually tend to have a lower risk of breast cancer, particularly hormone-sensitive types, for the same reasons as multiparous women — more pregnancies reduce hormonal exposure.